Oscillating Wall Fan A Light Bulb Is Connected To A Wall Socket Which Provides An Oscillating Voltage Emf=Vosin(omega X T) To The?

A light bulb is connected to a wall socket which provides an oscillating voltage emf=Vosin(omega x t) to the? - oscillating wall fan

A lamp is connected to the terminal that an oscillating voltage Vosin emf = (omega x) for the circuit and provides significantly associated lit. What happens after a piece of iron to put the light in a coil of wire in the circuit?
1. Sun
2. Lights
3. unchanged

4 comments:

nozar nazari said...

2.brightens

nyphdinm... said...

In an AC circuit is the power to the tension and intensity of the linked

P = V * I * cos (Q), where Q is the phase between voltage and current.

In a purely resistive circuit V and I are on PAHs and q = 0 for the results of Ohm's Law

P = V * I

In some bulb resistive and inductive part. The inductive part of the increase of q 0 is given by:

q = arctan (Z / R), where Z = Omega * L and L is the light bulb inudctance coil.

If you (a piece of iron in the coil space and if) no cut, then L increases, resulting in Z and Q. If Q increases, then

P = V * I * cos (q) decreases as the lamp is lower.

nyphdinm... said...

In an AC circuit is the power to the tension and intensity of the linked

P = V * I * cos (Q), where Q is the phase between voltage and current.

In a purely resistive circuit V and I are on PAHs and q = 0 for the results of Ohm's Law

P = V * I

In some bulb resistive and inductive part. The inductive part of the increase of q 0 is given by:

q = arctan (Z / R), where Z = Omega * L and L is the light bulb inudctance coil.

If you (a piece of iron in the coil space and if) no cut, then L increases, resulting in Z and Q. If Q increases, then

P = V * I * cos (q) decreases as the lamp is lower.

nyphdinm... said...

In an AC circuit is the power to the tension and intensity of the linked

P = V * I * cos (Q), where Q is the phase between voltage and current.

In a purely resistive circuit V and I are on PAHs and q = 0 for the results of Ohm's Law

P = V * I

In some bulb resistive and inductive part. The inductive part of the increase of q 0 is given by:

q = arctan (Z / R), where Z = Omega * L and L is the light bulb inudctance coil.

If you (a piece of iron in the coil space and if) no cut, then L increases, resulting in Z and Q. If Q increases, then

P = V * I * cos (q) decreases as the lamp is lower.

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